📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      There are 6 blue pens, 5 black pens and 4 green pens in

      a bag. Three pens are chosen randomly. Quantity I – The probability of their being 2 blue and 1 green pens. Quantity II – The probability of their being 1 blue, 1 black and 1 green pens. In each of the following questions, read the following questions, read the given statements and compare given two quantities on its basis:
      A Quantity I > Quantity II Correct Answer Incorrect Answer
      B Quantity I < Quantity II Correct Answer Incorrect Answer
      C Quantity I ≥ Quantity II Correct Answer Incorrect Answer
      D Quantity I ≤ Quantity II Correct Answer Incorrect Answer
      E Quantity I = Quantity II Correct Answer Incorrect Answer

      Solution

      Total number of pens = 6 + 5 + 4 = 15 Three pens are chosen at random. Then, n(S) = ¹⁵C₃ = (15 ×14 ×13 )/(3 ×2 ×1) = 130 Quantity I. n(E) = ⁶C₂ × ⁴C₁ = 15 × 4 = 60 P(E) = 60/130 = 6/13 Quantity II. n(E) = ⁶C₁ × ⁵C₁ × ⁴C₁ = 6 × 5 × 4 = 120 P(E) = 120/130 = 12/13 ∴ Quantity I < Quantity II.

      Practice Next
      More Equations Questions

      Relevant for Exams:

      ask-question