Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. x2– (2√3 + 3√2)x + 6√6 = 0 II. y2 - 5√2y + 12 = 0Solution
From I: x2 – (2√3 + 3√2)x + 6√6 = 0 x2 – 2√3x - 3√2x + 6√6 = 0 x (x – 2√3) – 3√2 (x – 2√3) = 0 (x – 2√3) (x – 3√2) = 0 x = 2√3, 3√2 From II: y2 - 5√2y + 12 = 0 y2 - 3√2y – 2√2y + 12 = 0 y (y – 3√2) – 2√2 (y – 3√2) = 0 (y – 3√2) (y – 2√2) = 0 y = 2√2, 3√2 Relationship cannot be established between x and y.
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 154Â Â Â Â 165Â Â Â Â 143Â Â Â Â 175Â Â Â Â Â 132Â Â Â Â Â 187
...5000, 4500, 3600, 2480, 1512, 756Â Â Â
Find the wrong number in the given number series,
125, 150, 250, 475, 875, 1500
- Find the wrong number in the given number series.
5, 8, 12, 19, 27, 39 768Â Â Â 2304Â Â Â 288Â Â Â 864Â Â Â 106Â Â Â 324
Find the wrong number in the given number series.
5, 6, 14, 45, 188, 925
120, 240, 80, 320, 60, 384
21 32 54 86 131 186
... 7    12     33    126    635  Â