Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. x2β (2β3 + 3β2)x + 6β6 = 0 II. y2 - 5β2y + 12 = 0Solution
From I: x2 β (2β3 + 3β2)x + 6β6 = 0 x2 β 2β3x - 3β2x + 6β6 = 0 x (x β 2β3) β 3β2 (x β 2β3) = 0 (x β 2β3) (x β 3β2) = 0 x = 2β3, 3β2 From II: y2 - 5β2y + 12 = 0 y2 - 3β2y β 2β2y + 12 = 0 y (y β 3β2) β 2β2 (y β 3β2) = 0 (y β 3β2) (y β 2β2) = 0 y = 2β2, 3β2 Relationship cannot be established between x and y.
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