Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. x2– (2√3 + 3√2)x + 6√6 = 0 II. y2 - 5√2y + 12 = 0Solution
From I: x2 – (2√3 + 3√2)x + 6√6 = 0 x2 – 2√3x - 3√2x + 6√6 = 0 x (x – 2√3) – 3√2 (x – 2√3) = 0 (x – 2√3) (x – 3√2) = 0 x = 2√3, 3√2 From II: y2 - 5√2y + 12 = 0 y2 - 3√2y – 2√2y + 12 = 0 y (y – 3√2) – 2√2 (y – 3√2) = 0 (y – 3√2) (y – 2√2) = 0 y = 2√2, 3√2 Relationship cannot be established between x and y.
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