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    Question

    Let 0 < x < 1, Then the correct inequality

    is
    A x < тИЪx < x^2 Correct Answer Incorrect Answer
    B тИЪx < x < x^2 Correct Answer Incorrect Answer
    C x^2 < x < тИЪx Correct Answer Incorrect Answer
    D тИЪx < x^2 < x Correct Answer Incorrect Answer

    Solution

    Let us take an example of 0.25 (0 < 0.252= .0625 $$\sqrt{0.25} =0.5 0.0625 < 0.25 < 0.5 So, the correct order is x2 < x So, the answer would be option c) x2 < x

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