Question
In a biased coin the probability of getting a head is
0.6, if we toss a coin 10times, what is the probability of getting exactly three heads?Solution
Probability of getting a head =0.6 =6/10=3/5 Probability of getting not head=1-3/5 =2/5 Direct shortcut- n Cr(P)r(1-P) n-r Then now Probability= =10C3 (3/5)3(2/5)7 = [(10Ă—9Ă—8)/3Ă—2] Ă— (33Ă—27)/510 = (34Ă—210)/59
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