Question
Find the average number of chocolates distributed in
class IV, V and VI together. Study the following line chart carefully and answer the questions given below: The following pie chart shows the percentage distribution of chocolates to the students studying in five different classes (i.e. II, III, IV, V and VI) Total number of chocolates = 2500Solution
Number of chocolates distributed in class IV = (18/100) × 2500 = 450 Number of chocolates distributed in class V = (32/100) × 2500 = 800 Number of chocolates distributed in class VI = (10/100) × 2500 = 250 Required average = (450 + 800 + 250)/3 = 500
52% of 400 + √(?) = 60% of 600 - 25% of 400
What value should come in the place of (?) in the following questions?
(7/9) of (15/4) of 480 = ?
Simplify the following expression:
36895 - 4256 - 2233 = ?Â
What will come in the place of question mark (?) in the given expression?
23 X 35 - ? = (132 + 16) X 3 + 25
(744 ÷ 6) - (120/5) + 5.5% of 800 = ?2
What will come in the place of question mark (?) in the given expression?
(243/9) X 5 - 112 = ? ÷ (24 - 13)
What value should come in the place of (?) in the following questions?
40% of 480 + √? = 25% of 300 + 126
30% of 2200 +’?’ x 50 – 1020 = 11x 306 + (√ 2250 ÷ 0.1) Â
What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?
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