In how many days can 16 men and 8 women together complete a piece of work?
I. 8 men complete the piece of work in 10 days.
II. 16 women complete the piece of work in 10 days.
III. 5 women take 32 days to complete the piece of work.
From I & II, 8 Men → 10 days 16 Men → (10 × 8)/16 = 5 days. 16 women → 10 days 8 women → (10 × 16)/8 = 20 days. (16 Men + 8 women)’s work = 1/5 + 1/20 = 1/4 16 Men and 8 women can complete in 4 days. From I & III, 8 Men → 10 days 16 Men → (10 × 8)/16 = 5 days. 5 women → 32 days 8 women → (5 × 32)/8 = 20 days. (16 Men + 8 women)’s work = 1/5 + 1/20 = 1/4 16 Men and 8 women can complete in 4 days. Hence statement I and either II or III is sufficient to answer the question.
36% of 540 – (45% of 7300) ÷ 75 =?
((9.77)^0- 〖(0.1)〗^(-1))/(〖(6/2^4 )〗^(-1) ×(3/2)^3+ 〖((-2)/6)〗^(-1) ) = ?
(2/3) × (5/7) × (3/4) × ? = 80
(53 + 480 ÷ 4)% of 20 = ?% of 70
2916 ÷ 54 = ? + 27
(30 × 0.80)⁴ ÷ (2160 ÷ 60)⁴ × (54 × 16)⁴ = (6 × 4)?+5
15% of 695 – 12.5% of 250 =? – 1200
120% of 400 + ?% of 520 = 1000
If x - 1/x = 9, then the value of x² + 1/ x² is:
360 ÷ 4 ÷ 3 = 150 – ?