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given CI= 1623, T= 2.5year, r= 10% after 2 years rate of interest count in half-yearly then will be r= 5% Let P=x then A= CI-P=1623-x So now 1623-x = x [1+10/100] ² [1+5/100] 1623-x = x [121/100] [21/20] 1623-x =x [2541/2000] (1623×2000-2000x) =2541x 541x=1623×2000 x= 1623×2000/541 x=6000rs short method –r= 10%=1/10 then P A 10 11 first year 10 11 second year 20 21 After 2year rate of interest count will be half-yearly then r=5% =1/20 2000 2541 CI=A-P=2541-2000=541 but ATQ compound interest is 1623 So 541=1623 1=1623/541 Then P 2000=1623×2000/541 P= 6000rs
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
175 + 24% of 450 = 350 + ?
(60 × 8 ÷ 10) × 5 = ?
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
What will come in place of the question mark (?) in the following questions?
(122 - 82 ) X ? = 90% of 500 - (90 - 25) X 2
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
Simplify-
x + 3(y + x – 2) – (x + y).
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5