Two parallel chords of a circle of diameter 20 cm are 12 cm and 16 cm long. If the chords are on the same side of the center, what is the distance between them?
Using the right triangle formed by the chord of 12 cm: OB ² = 10 ² - 6 ² = 8 ² then OB = 8 cm Using the right triangle formed by the chord of 16 cm: OA ² = 10 ² - 8 ² = 6 ² then OA = 6 cm Then then the distance between two chords = OB - OA = 8 - 6 = 2 cm