Three circles of radii 4.8 cm, 3.2 cm, and 5.4 cm touch each other externally. What is the perimeter of the triangle formed by joining the centers of the circles (in cm)?
Side PQ = 4.8 + 5.4 = 10.2 Side PR = 5.4 + 3.2 = 8.6 Side QR = 3.2 + 4.8 = 8 Perimeter = 10.2 + 8.6 + 8 = 26.8
