ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!


    Question

    In the given diagram, point 'O' represents the center of

    a circle, while AB and DE are two distinct chords within the circle. The line segment OC is perpendicular to the chord AB, and the segment OF is perpendicular to the chord DE. The length of chord AB is provided as 24 cm, and the distance CF from the center to the perpendicular intersection with chord DE is (5 + 4тИЪ5) cm. The radius of the circle measures 13 cm. Determine the length of chord DE.
    A 2тИЪ89 cm Correct Answer Incorrect Answer
    B 3тИЪ69 cm Correct Answer Incorrect Answer
    C 4тИЪ49 cm Correct Answer Incorrect Answer
    D 8тИЪ5 cm Correct Answer Incorrect Answer

    Solution

    The perpendicular from the centre of the circle to its chord, bisects the chord. So, AC = CB = (24/2) = 12 cm Similarly, DF = FE In right rAOC, using Pythagoras theorem, AO2┬а= AC2┬а+ CO2 Or, 132┬а= 122┬а+ CO2 So, CO2┬а= 169 - 144 = 25 Or, CO = тИЪ25 = 5 cm And, OF = CF - CO = 5 + 4тИЪ5 - 5 = 4тИЪ5 cm In right rDOF, using Pythagoras theorem, DO2┬а= DF2┬а+ OF2 So, DF2┬а= 132┬а- (4тИЪ5)2 Or, DF2┬а= 169 - 80 = 89 So, DF = тИЪ89 cm DE = DF + FE = 2DF = 2тИЪ89 cm┬а

    Practice Next
    More Circle Questions
    ask-question