Work = Total number of men × Total days M1D1/W1 = M2D2/W2 Let the efficiency of 1 man be M. And the efficiency of 1 woman is W. According to the question, 2 men and 7 women complete a work in 28 days = 6 men and 16 women complete the same work in 11 days ⇒ (2M + 7W) × 28 = (6M + 16W) × 11 ⇒ 56M + 196W = 66M + 176W ⇒ 10M = 20W ⇒ M = 2W 2 men and 7 women = 2M + 7W ⇒ 2 men and 7 women = 4W + 7W ⇒ 2 men and 7 women = 11W 5 men and 4 women = 5M + 4W ⇒ 5 men and 4 women = 10W + 4W ⇒ 5 men and 4 women = 14W M2D2/W2 = M2D2/W2 ⇒ 11W × 28 = 14W × D2 ⇒ D2 = 22 days ∴ 5 men and 4 women, working together, complete the same work in 22 days.
55, 71, 119, 199, 311, ?
2 3 5 9 ? 33
...The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
140, 146, 170, 224, ?, 470
79 86 76 89 73 ?
...17, 19, 41, 127, 513, ?
23, 28, 38, 49, 62, ?
115, 138, 163, 190, 219, ?
14, 20, ?, 50, 74, 104
42 63 126 189 378 ?
