Question
If a man rows at the rate of 25 kmph in still
water and his rate against the current is 5.5 kmph, then the manrsquo;s rate along the current is:Solution
Let manrsquo;s speed downstream be x kmph. Manrsquo;s rate in still water = (x + 5.5)times; frac12; kmph 25 = (x + 5.5)times; frac12; kmph 50 = (x + 5.5) kmph x = 50 ndash; 5.5 = 44.5 kmph
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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What is the code for ‘it’?
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