Question
The speed of boat downstream and upstream is 36 km/hr
and 26 km/hr respectively. Time taken to travel a distance of (k + 60) km downstream and (l + 40) km upstream is 16 hours, and time taken to travel (k + 120) km upstream and (l + 80) km downstream is 22 hours. Find the approximate difference between the value of k and value of l.Solution
ATQ,
We are given: The speed of the boat downstream = 36 km/h The speed of the boat upstream = 26 km/h The time for traveling (k+60) km downstream and (l+40) km upstream is 16 hours. The time for traveling (k+120) km upstream and (l+80) km downstream is 22 hours. 
After solving these equations, we find: k=321.86 and l = 100.23 The difference between k and l is: k − l = 321.86 − 100.23 = 221.63 So, the difference between k and l is 221.63.
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...
Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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