Question
The speed of a boat in still water is twice the speed of
the current. The difference between downstream and upstream speeds is 16 km/h. If the boat spends 10 hours to travel the same distance 'q' km each way, find 'q'.Solution
ATQ, Let the speed of the stream = t km/h Speed of the boat in still water = 2t km/h Upstream speed of the boat = 2t – t = t km/h Downstream speed of the boat = 2t + t = 3t km/h Difference in Speed: - 3t - t = 2t = 16 km/h, so, t = 8 km/h Calculate the time for each distance 'q': 
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
