Question
The ratio of the speed of boat βAβ in still water,
the speed of boat βBβ in still water and the speed of the current is 8:6:2, respectively. If the time taken by boat βAβ to travel (5D β 45) km downstream is equal to the time taken by boat βBβ to travel (D + 80) km upstream, then find the value of βDβ.Solution
Let, the speeds of boat βAβ and boat βBβ, in still water and the speed of the current be 8x km/hr, 6x km/hr and 2x km/hr, respectively. According to the question, (5D β 45)/(8x + 2x) = (D + 80)/(6x β 2x) Or, 20D β 180 = 10D + 800 Or, 10D = 980 Or, D = 98
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