Question
The speed of the stream is 10 km/h. Boat βAβ covers
88 km distance against the stream in 11 hours and boat βBβ covers 106 km distance against the stream in 2 hours. The speed of boat βBβ in still water is how much percent of the speed of boat βAβ in still water?Solution
Speed of boat βAβ upstream = 88/11 = 8 km/h Speed of boat βBβ upstream = 106/2 = 53 km/h Speed of the boat βAβ in still water = 8 + 10 = 18 km/h Speed of the boat βBβ in still water = 53 + 10 = 63 km/h Required percentage = (63/18) Γ 100 = 350%
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