Find both the maximum value and the minimum value respectively of 3a4 minus; 8a3 + 12a2 minus; 48a + 25 on the interval [0, 3].
Given, f(a) = 3a4 minus; 8a3 + 12a2 minus; 48a + 25 fprime;(a) = 12a3 minus; 24a2 + 24a minus; 48 = 12(a3 minus;2a2 + 2a minus;4) = 12[a2(a minus; 2) + 2(a minus; 2)] = 12(a2 + 2)(a minus; 2) For maxima and minima, fprime;(a) = 0 =gt; 12(a2 + 2)(a minus; 2)=0 =gt; a = 2, a2 = -2 Since a2 = -2 is not possible So, a = 2 isin; [0, 3] Now we evaluate the value of f at critical point a = 2 and at the end points of the interval [0, 3] f(0) = 25 f(2) = 3 times; 24 ndash; 8 times; 23 + 12 times; 22 ndash; 48 times; 2 + 25 = 48 ndash; 64 + 48 ndash; 96 + 25 = minus;39 f(3) = 3 times; 34 ndash; 8 times; 33 + 12 times; 32 ndash; 48 times; 3 + 25 = 243 ndash; 216 + 108 minus;144 + 25 = 16 Hence, at a = 0, Maximum value = 25 At a = 2, Minimum value = -39
Which of the following is the largest storage?
What's the common term for an error within a computer program's code that prevents it from functioning properly?
----- represents the correct sequence for copy, paste and cut commands?
The difference between the EPROM and ROM circuitry is _____
CAD stands for
In programming, repeating some statements is usually called
In which of the following communication system, both the sender and receiver can transfer the information at the same time?
Which of the following algorithms is used to avoid deadlock?
A logical schema
What is the shortcut key to Maximise the document window ?