Question
If the sum of the coefficients of all even powers of x
in the product (1 + x + x2 + β¦ + x2n) (1 β x + x2 β x3 + β¦ + x2n) is 89, then find the value of n.Solution
Let (1 + x + x2 + β¦ + x2n) (1 β x + x2 β x3 + β¦ + x2n) = a0 + a1 + a2 + a3+ β¦β¦ Put x = 1 => 2n + 1 = a0 + a1 + a2 + a3 + β¦β¦ β¦(i) Put x = -1 => 2n + 1 = a0 β a1 + a2 β a3 + β¦β¦ β¦..(ii) Add (i) and (ii), we get 2n + 1 = 89 Or n = 44
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