Question
The average length of 60 pipes is 120 cm. When two pipes
of lengths (n + 15) cm and (n - 5) cm are added, the average length becomes 121 cm. Find the value of (n - 100).Solution
ATQ, New number of pipes = 60 + 2 = 62 New average length = 121 62 × 121 - 60 × 120 = (n + 15) + (n - 5) Or, 62 × 121 - 60 × 120 = 2n + 10 Or, 7502 - 7200 = 2n + 10 Or, 302 = 2n + 10 Or, 2n = 292 Or, n = 146 Therefore, required value = n - 100 = 146 - 100 = 46
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
Simplify the following expressions and choose the correct option.
40% of 360 + 25% of 248 - 30
Evaluate
32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 + 5)] + (6 ÷ 2 + 1)
√324 + √576 = ?/ √9
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
- 60% of 180 – 30% of 60 = 15% of ?
40% of 50 + 50% of ? = 25% of 300 - 10% of 250
`sqrt(7744)` Â Â -Â `sqrt(4761)` +Â `sqrt(8281)` Â +Â `sqrt(5625)` + ? = 1856Â
What will come in the place of question mark (?) in the given expression?
(11/45) of 225 + 3 X 75 = ? X (72 ÷ 6 + 4)
Find the simplified value of the given expression.
(9.6 × 15 – 4.6 × 5) �...
