Question
The average length of 60 pipes is 120 cm. When two pipes
of lengths (n + 15) cm and (n - 5) cm are added, the average length becomes 121 cm. Find the value of (n - 100).Solution
ATQ, New number of pipes = 60 + 2 = 62 New average length = 121 62 × 121 - 60 × 120 = (n + 15) + (n - 5) Or, 62 × 121 - 60 × 120 = 2n + 10 Or, 7502 - 7200 = 2n + 10 Or, 302 = 2n + 10 Or, 2n = 292 Or, n = 146 Therefore, required value = n - 100 = 146 - 100 = 46
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