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    Question

    There are three numbers 'd', 'e' and 'f' such that

    average of 'd' and 'e' is 10, average of 'e' and 'f' is 22 and average of 'd' and 'f' is 28. Find the average of 'd', 'e' and 'f'.
    A 18 Correct Answer Incorrect Answer
    B 19 Correct Answer Incorrect Answer
    C 20 Correct Answer Incorrect Answer
    D 21 Correct Answer Incorrect Answer

    Solution

    d + e = 2 × 10
    Or, d + e = 20 -------- (I)
    e + f = 2 × 22
    Or, e + f = 44 -------- (II)
    d + f = 2 × 28
    Or, d + f = 56 -------- (III)
    On adding equations I, II and III,
    We get, d + e + e + f + d + f = 20 + 44 + 56
    Or, 2 × (d + e + f) = 120
    Or, d + e + f = 60
    Therefore, required average = (60/3) = 20

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