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      Question

      There are three numbers 'd', 'e' and 'f' such that

      average of 'd' and 'e' is 10, average of 'e' and 'f' is 22 and average of 'd' and 'f' is 28. Find the average of 'd', 'e' and 'f'.
      A 18 Correct Answer Incorrect Answer
      B 19 Correct Answer Incorrect Answer
      C 20 Correct Answer Incorrect Answer
      D 21 Correct Answer Incorrect Answer

      Solution

      d + e = 2 × 10
      Or, d + e = 20 -------- (I)
      e + f = 2 × 22
      Or, e + f = 44 -------- (II)
      d + f = 2 × 28
      Or, d + f = 56 -------- (III)
      On adding equations I, II and III,
      We get, d + e + e + f + d + f = 20 + 44 + 56
      Or, 2 × (d + e + f) = 120
      Or, d + e + f = 60
      Therefore, required average = (60/3) = 20

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