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ATQ,
Sum of twenty numbers = (20 × 40) = 800
Sum of the first ten numbers = (10 × 48) = 480
Sum of the last ten numbers = (10 × 56) = 560
So, tenth term = 480 + 560 - 800 = 240
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
? = 120% of (652 ÷ 132 ) + 33 × 8
?= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
√289 + √49 + 121 =?
Solve for ?.
∛21952 × 44 = ? × 14
Find the simplified value of the following expression:
72 + 132 X 4 - {232 + 172 - 402