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S1: 3, 5, 7, 11 and 13
First term of S2 = 4th term of S1 = 11
S2: 11, 13, 15, 17 and 19.
Let S3: a, a + 2, a + 4, a + 6 and a + 8
Average of S3 = 6
(5a + 20)/5 = 6
=> a + 4 = 6
=> a = 2.
S3: 2, 4, 6, 8 and 10
Difference between the greatest term of S3 to the middle term of S2
= 10 - 15 = −5
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