πŸ“’ Too many exams? Don’t know which one suits you best? Book Your Free Expert πŸ‘‰ call Now!

    Question

    The combined average number of pens with persons β€˜B’

    and β€˜C’ is 75% of the combined average number of pens with persons β€˜A’ and β€˜D’. The overall average number of pens with all four persons is 45.5, and person β€˜A’ has 16 fewer pens than person β€˜D’. Based on this information, what is the average number of pens with persons β€˜B’, β€˜C’, and β€˜D’ together?
    A 48 Correct Answer Incorrect Answer
    B 54 Correct Answer Incorrect Answer
    C 40 Correct Answer Incorrect Answer
    D 46 Correct Answer Incorrect Answer

    Solution

    Let the number of pens with β€˜A’ and β€˜D’ be β€˜x’ and β€˜y’, respectively According to the question, Average number of pens with β€˜B’ and β€˜C’ = {(x + y)/2} Γ— 0.75 So, sum of number of pens with β€˜B’ and β€˜C’ = {3(x + y)/4} So, sum of number of pens with all 4 persons = (x + y) + {3(x + y)/4} = (7x + 7y)/4 According to the question, (7x + 7y)/16 = 45.5 Or, (x + y) = 45.5 Γ— 16 Γ· 7 = 104 Or, x = y – 16 So, y + y – 16 = 104 y = (104 +16)/2 = 120/2 = 60 So, number of pens with β€˜D’ = 60 Number of pens with β€˜A’ = 60 – 16 = 44 So, sum of number of pens with β€˜B’ and β€˜C’ = (44 + 60) Γ— 0.75 = 78 So, average number of pens with β€˜B’, β€˜C’ and β€˜D’ = {(78 + 60)/3} = 138/3 = 46Β 

    Practice Next
    More Average Questions
    ask-question