Question
Average of A, B and C is 30 and
that of C, D and E is 19. The average of A and E is 23 and that of B and E is 24. Find the value of B.Solution
ATQ,
From the equations derived: A+B+C=90 C+D+E=57 A+E=46 B+E=48 We expressed everything in terms of A: E=46−A B=2+A C=88−2A D=3A−77 However, no unique value of A is determined from these equations because the system of equations is under determined. There are more variables (A,B,C,D,E) than independent equations. This means multiple sets of values can satisfy the equations, making it impossible to uniquely determine B. Thus, the answer is indeed "cannot be determined."
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