Question
The average weight of 4 persons is 50 kg. The heaviest
person’s weight is 20 kg more than the lightest person’s weight. If the average weight of the rest two persons is 50 kg, then find the weight of the heaviest person.Solution
The sum of the weight of 4 persons = 50 × 4 = 200 kg Let the weight of the lightest person = ‘x’ kg The weight of the heaviest person = (x + 20) kg The sum of the weight of the remaining two persons = 50 × 2 = 100 kg According to the question, x + x + 20 + 100 = 200 2x = 80 x = 40 The weight of the heaviest person = 40 + 20 = 60 kg
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