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Start learning 50% faster. Sign in nowLet the average weight of class be x. and weight of teacher be t. so, Total weight of 5 students = 5x Now, average weight is also included then, (5x + t)/6 = x + 4 5x + t = 6x + 24 t – x = 24 t = x + 24------(i) AQT, x + t = 104 2t – 24 = 104 t = 64
If tanθ – cotθ = a and cosθ + sinθ = b, then (b2 –1)(a2 + 4) = ?
What is the value of 1/(1+tan 2θ ) + 1 / (1+cot 2 θ ) = ?
...What is the value of sin(B – C) cos(A – D) + sin(A – B) cos(C – D) + sin(C – A) cos(B – D)?
If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is
The value of (3tan10°-tan³10°)/(1-3tan²10°) is equal to
Solve the following trigonometric expression:
Find the value of the following:sin(36° + A) × cos(54° – A) + cos(36° + A) × sin(54°–A)
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...If sec(2A + B) = 2 and cos(A + B) = (1/√2) , find the value of {sec 2B + tan (A + B) } given that 0o < A, B < 90o
If sin (2x + 50) o = cos (2y - 50) o, such that, 0o < x + y < 90o, then find the value of tan(x + y) .
