Question
Cities X and Y are 180 km away from each other. A bike
leaves from city X towards city Y at 8 am at a speed of 36 km/h. At 10 am, another bike starts from city Y towards city X at 24 km/h. When will the two bikes meet?Solution
ATQ,
Distance covered by first bike till 10 am = 36 × 2 = 72 km Remaining distance = 180 – 72 = 108 km Time taken by both bikes to meet each other = 108 / (36 + 24) = 108 / 60 = 1.8 hours = 1 hour 48 minutes They will meet at 10:00 + 1 hour 48 minutes = 11:48 am
7480 ÷ 16.98 – 34.32 ÷ (4.99/99.9) = ?
? = 25.08 + 11.99 × 24.07
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(7.992/√?) + √16/? = 14.032/?
11.992 + (6.01 × 5.98) + ? = 350.03
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, find the value of (4A - B) .
At a village trade fair a man buys a horse and a camel together for Rs 51,250. He sold the horse at a profit of 25 % and the camel at a loss of 20 %. If...
? = 650.24 + 1124.97 – 14.992
? × [(16.87) 2 – (6.98) 2 ] = 5.04× 191.11
3.934 - 124.07 + 35.94 + 12.83 of 4.85 - 84.76 ÷ √26 = ?3
