Question
Cities X and Y are 180 km away from each other. A bike
leaves from city X towards city Y at 8 am at a speed of 36 km/h. At 10 am, another bike starts from city Y towards city X at 24 km/h. When will the two bikes meet?Solution
ATQ,
Distance covered by first bike till 10 am = 36 × 2 = 72 km Remaining distance = 180 – 72 = 108 km Time taken by both bikes to meet each other = 108 / (36 + 24) = 108 / 60 = 1.8 hours = 1 hour 48 minutes They will meet at 10:00 + 1 hour 48 minutes = 11:48 am
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