Question
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of
1980 What approximate value should come in place of the Question mark (?) in the given equation.Solution
158% of 4820 + 92% of 2840 = ? + 116% of 1980 (100% of 4820 + 50% of 4820 + 8% of 4820) + (100% of 2840 – 8% of 2840) = ? + (100% of 1980 + 10% of 1980 + 6% of 1980) (4820+2410+385.6) +(2840-227.2) = ? +(1980+198+118.8) 7616+2613=?+2297 ? = 7932
(292 – 141) ÷ 5 + (40 ÷ 2) + 23 = ?
56 x 8 – 65% of 40 = ? + 14 x √625
16 × ? + 36% of 250 = 410
35% of 240 – 6 2 = ? 2 – √256
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
[{70 + (40 - 22) ÷ 3} ÷ 4] = ?
33 + (6.25) % of 1600 = ? + 2 X 55
115% of 40 + 3 × 4 = ? × 11 – 8