Question
If 120 liters of milk solution contains 60% milk, how
much milk should be added to make the solution 80% milk?Solution
ATQ, Total volume: 120 liters Milk content: 60% of 120 liters = 72 liters Let x be the amount of milk to add. Then, Total volume: 120+x liters Milk content: 72+x liters Hence, Desired concentration will be 80% milk So, Set up the equation: Now, Solve for x: 72+x = 0.80×(120+x) 72+x = 96+0.80x 0.20x = 24 x = 120 Therefore, you need to add 120 liters of milk to make the solution 80% milk.
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5³ + 3²) Ă— 2 = ? (1225/25) - (192/96) + (50/5) = ?

What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) Ă· 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 – 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650