Question
If 120 liters of milk solution contains 60% milk, how
much milk should be added to make the solution 80% milk?Solution
ATQ, Total volume: 120 liters Milk content: 60% of 120 liters = 72 liters Let x be the amount of milk to add. Then, Total volume: 120+x liters Milk content: 72+x liters Hence, Desired concentration will be 80% milk So, Set up the equation: 
Now, Solve for x: 72+x = 0.80×(120+x) 72+x = 96+0.80x 0.20x = 24 x = 120 Therefore, you need to add 120 liters of milk to make the solution 80% milk.
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