Question
If, ( a + b = 8 ) and ( aĀ² + bĀ² = 40 ), then find the
value of (aĀ³ + bĀ³).ĀSolution
( a + b = 8 )
( (a + b) Ā² = 8Ā² )
( aĀ² + bĀ² + 2ab = 64 )
( 40 + 2ab = 64 )
( 2ab = 24 ab = 12 )
( aĀ³ + bĀ³ = (a + b)(aĀ² + bĀ² - ab)) = 8 (40 - 12) = 8Ā * 28 = 224Ā
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