Question
If p = 28 - q - r and pq + r(p + q) = 231, then find the
value of (p² + q² + r²).Solution
We have, p = 28 - q - r
So, p + q + r = 28
And, pq + r(p + q) = 231
Or, pq + qr + pr = 231
Using, (p + q + r)² = p² + q² + r² + 2(pq + qr + pr)
28² = (p² + q² + r²) + 2 × 231
784 = (p² + q² + r²) + 462
p² + q² + r² = 322
More Algebra Questions
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
√(24²+285-8²-172) = ?²
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