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Section 116. Abetment of offence punishable with imprisonment—if offence be not committed—Whoever abets an offence punishable with imprisonment shall, if that offence be not committed in consequence of the abetment, and no express provision is made by this Code for the punishment of such abetment, be punished with imprisonment of any description provided for that offence for a term which may extend to one-fourth part of the longest term provided for that offence; or with such fine as is provided for that offence, or with both; If abettor or person abetted be a public servant whose duty it is to prevent offence.—and if the abettor or the person abetted is a public servant, whose duty it is to prevent the commission of such offence, the abettor shall be punished with imprisonment of any description provided for that offence, for a term which may extend to one-half of the longest term provided for that offence, or with such fine as is provided for the offence, or with both. (c) A, a police-officer, whose duty it is to prevent robbery, abets the commission of robbery. Here, though the robbery be not committed, A is liable to one-half of the longest term of imprisonment provided for that offence, and also to fine.
Two numbers are in the ratio 7:5. After adding 2 and 4 to them respectively the ratio becomes 2:3. Find the bigger number.
A box contains the coins of 5p, 10p and 25p are in the ratio 3:4:6. If there is Rs. 82 in all, how many 10p coins are there?
A sum of Rs.1000 is divided among P, Q and R such that P gets Rs.150 more than Q. Q gets Rs.110 more than R. How much does R receive?
A sum of money is divided in the ratio of 5:9. If the smaller part is 405. Find the larger part.
If the mean proportion of 4.8 and 1.2 is denoted by 'k', then determine the value of '5k'.
What is the fourth proportion of 16, 20 and 24?
The ratio of two numbers is 6:7. If each number is decreased by 3, the ratio becomes 9:11. Find the smaller numbers.