Question
A computer system has a cache memory with an access time of 10 ns and a main memory with an access time of 100 ns. If the cache hit ratio is 95%, what is the average memory access time?
Solution
Average Access Time = (Hit Ratio * Cache Access Time) + (Miss Ratio * Main Memory Access Time) = (0.95 * 10 ns) + (0.05 * 100 ns) = 9.5 ns + 5 ns = 14.5 ns
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