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    Question

    A computer system has a cache memory with an access time

    of 10 ns and a main memory with an access time of 100 ns. If the cache hit ratio is 95%, what is the average memory access time?
    A 10 ns Correct Answer Incorrect Answer
    B 14.5 ns Correct Answer Incorrect Answer
    C 19 ns Correct Answer Incorrect Answer
    D 55 ns Correct Answer Incorrect Answer
    E 95 ns Correct Answer Incorrect Answer

    Solution

    Average Access Time = (Hit Ratio * Cache Access Time) + (Miss Ratio * Main Memory Access Time) = (0.95 * 10 ns) + (0.05 * 100 ns) = 9.5 ns + 5 ns = 14.5 ns

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