In C++, how is abstraction primarily achieved when defining a class that cannot be instantiated directly but serves as a blueprint for derived classes?

Q: Answer-In C++, how is abstraction primarily achieved when defining a class that cannot be instantiated dire...

o In C, a class is considered an abstract base class if it has at least one pure virtual function. A pure virtual function is declared by assigning 0 to it in the base classs declaration e.g., virtual void func 0. o Abstract classes cannot be instantiated directly. They serve as interfaces or blueprints, forcing derived classes to provide implementations for all pure virtual functions to become concrete instantiable.

A By making all member variables `private`. Correct Incorrect

B By using the `virtual` keyword for all methods. Correct Incorrect

C By declaring at least one pure virtual function (e.g., `virtual void func() = 0;`). Correct Incorrect

D By making the constructor `protected`. Correct Incorrect

E By using the `abstract` keyword (which does not exist in C++). Correct Incorrect

Detailed Solution

o In C++, a class is considered an abstract base class if it has at least one pure virtual function. A pure virtual function is declared by assigning = 0 to it in the base class's declaration (e.g., virtual void func() = 0;). o Abstract classes cannot be instantiated directly. They serve as interfaces or blueprints, forcing derived classes to provide implementations for all pure virtual functions to become concrete (instantiable).

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In C++, how is abstraction primarily achieved when defining a class that cannot be instantiated directly but serves as a blueprint for derived classes?

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