In a Ternary Search algorithm, the array is divided into

Solution

Correct Answer: A (Integer division // is typically used in Python, but the mathematical expression is (high - low) / 3 for the segment length.) • Code Analysis: o The goal is to divide the range [low, high] into three roughly equal parts. o mid1 should be at approximately one-third of the way from low. o mid2 should be at approximately two-thirds of the way from low, or one-third of the way from high (working backward). • Explanation of Correct Answer (A): mid1 = low + (high - low) // 3, mid2 = high - (high - low) // 3 o high - low gives the length of the current search interval. o (high - low) // 3 calculates approximately one-third of this length using integer division. o mid1 = low + (high - low) // 3: This correctly places mid1 one-third of the way from low. o mid2 = high - (high - low) // 3: This correctly places mid2 one-third of the way back from high, effectively making it two-thirds of the way from low. This method avoids potential overflow issues that (low + high) * 2 // 3 might have with very large low and high values, and ensures mid1 and mid2 are distinct and within the bounds.