Question
A system uses a 32-bit logical address space and a page
size of 4KB. If each page table entry (PTE) is 4 bytes, how many entries can a single-level page table contain?Solution
Logical address space = 2^32 bytes. Page size = 4KB = 2^12 bytes. Number of pages = 2^32 / 2^12 = 2^20. Each page corresponds to one entry in the page table.
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