Question
Given a 16-bit instruction format with 4 bits for the
opcode and 12 bits for the address, calculate the maximum number of different opcodes that can be accommodated.Solution
The number of different opcodes that can be accommodated is given by 2^n, where n is the number of bits dedicated to the opcode. In this case, n = 4 (4 bits for opcode) Maximum number of opcodes = 2^4 = 16
Find the wrong number in the given series.
60, 65, 75, 95, 125, 195, 355
A series is given with one wrong term. Select the correct alternative from the given ones that will complete the series.
33, 44, 66, 110, 199, 374
Find the wrong number in the series given below.
3, 10, 89, 99, 301, 908
Identify the letter-cluster that does not belong to the following series.
RBK, TYM, VVO, XSP, ZPS, BMU
Select the wrong term in the series.
44, 47, 41, 50, 38, 53, 40
In the following question, select the wrong number from the given alternatives.
48, 50, 52, 57, 59, 68, 75
In the following question, select the wrong number from the given alternatives.
32, 16, 16, 24, 48, 126, 360
5, 15, 30, 135, 405, 1215, 3645
Select the wrong term from the given series?
RFD, OBY, LXT, ITO, FSK
Select the number from among the given options that is wrong in the following series.
22, 30, 46, 78, 146, 270
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