Given a 16-bit instruction format with 4 bits for the opcode and 12 bits for the address, calculate the maximum number of different opcodes that can be accommodated.
The number of different opcodes that can be accommodated is given by 2^n, where n is the number of bits dedicated to the opcode. In this case, n = 4 (4 bits for opcode) Maximum number of opcodes = 2^4 = 16
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No chair is a table.
...
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Some tablet are computer.
Conclusions: I. A...
Statement:
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All shirts are pant.
Some pants are not blazers.
Conclusion:
I. Some blaze...
Statements:
All tables are chairs.
All chairs are fan.
Some fan are bulb.
Conclusion:
I. All chairs are tables....
Statement:
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Some Guava is Leopard.
Some Leop...
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Only Sun are Moon.
Only few Sun are Star.
All Star are Gas.
Conclusion:
I. Some Gas are Moon.
...Statement:
Only Earth is Sun
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Some Doctor are not Lawyer
100% Lawyer are Teacher
Conclusions:
I. Some Lawyer are...
