Question
Consider a B+-tree in which the maximum number of keys
in a node is 5. What is the minimum number of keys in any non-root node?ΒSolution
Assuming order of B+ tree as p, maximum number of keys will be (p β 1). As it is given that, p β 1 = 5 => p = 6 Therefore, minimum number of keys: ceil(p/2) β 1 = 2 Β
Find the third proportion of β 2, β 7 and β 21. Β Β
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