Question
Consider a B+-tree in which the maximum number of keys
in a node is 5. What is the minimum number of keys in any non-root node?Solution
Assuming order of B+ tree as p, maximum number of keys will be (p – 1). As it is given that, p – 1 = 5 => p = 6 Therefore, minimum number of keys: ceil(p/2) – 1 = 2
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