Question
In a snowflake schema of a data warehouse, which of the
following consequences is most likely as a result of normalization of dimension tables?Solution
A snowflake schema is a variation of a star schema in which the dimension tables are normalized (broken down into related tables). This: • Reduces redundancy (e.g., separating country, state, and city into different tables). • Leads to better storage efficiency. • However, it requires more joins in queries, which can reduce query performance compared to a star schema. • Option A is incorrect because normalization typically increases the number of joins, decreasing performance. • Option C is false; more joins are needed in snowflake schemas. • Option D is incorrect; multiple dimension tables can be used. • Option E is the opposite of what a snowflake schema does (it normalizes, not denormalizes, dimension tables).
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
What will come in place of (?) in the given expression.
(18 + 24 ÷ 6) × 2 - 5 = ?What should come in place of (?) question mark in the given expression.
(4/9 of 729) + √1225 = ?
12(3/5) + 4(1/5) × 3(2/3) =?
- What will come in place of (?), in the given expression.
(5³ + 3²) × 2 = ? (5832) 2/3 / (104976)3/4 X ? = ( `sqrt(18)` ` ` ) 5
...46.2 × 8.4 × 3 + ? = 1200
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
{(5/8) + (4/5)} × (?/19) = 33