Question
A company uses a firewall to filter incoming and
outgoing network traffic. Despite this, an attacker successfully accesses the network through a vulnerability in an employee’s workstation. Which additional security measure would have helped prevent this attack?Solution
A firewall is effective for filtering network traffic but cannot secure endpoints, such as employee workstations, against vulnerabilities or targeted attacks. Endpoint Detection and Response (EDR) tools: 1. Monitor and analyze endpoint activities for suspicious behavior. 2. Detect and mitigate threats like malware or unauthorized access in real-time. 3. Provide visibility into individual devices, complementing network-level defenses. By implementing EDR, organizations gain robust protection for endpoints, reducing the likelihood of breaches. Why Other Options Are Incorrect: • A) Hardware-based firewall: Enhances performance but does not protect endpoints directly. • C) Increasing firewall rules: Focuses only on network traffic, leaving endpoints vulnerable. • D) Disabling VPN access: Restricting remote access doesn't address the workstation’s vulnerability. • E) Restricting social media: While reducing distractions, this measure doesn’t enhance security.
Statements: O < D ≤ T; C ≥ X = U; Y < Z = C > D
Conclusions:
I. U ≤ Z
II. O ≤ C
III. Y < D
Statements: R = S > Y ≥ T = W ≥ U > V > X
Conclusions:
I. Y < X
II. S > V
III. U ≤ RStatements: E > G < H > F = I ≥ J > K ≥ D
Conclusion
I: J < H
II: I > D
Statements:
F > L = P ≥ Q ≥ W; X < C ≤ D < W
Conclusions:
I. W > X
II. F > C
Statements: H ≥ D = R > I < M > U > P ≤ N
Conclusion I: H > R
II: P < M
Statements: Q © E, S % C, E $ S, C @ AÂ
Conclusions:Â
I. A © CÂ
II. S % AÂ
III. C © Q
Which among the following symbols should replace the question mark [?] (in the same order from left to right) in the given expression in order to make b...
Statements: X = P ≥ M; M > M > I > L; P < L < G
Conclusions:
I. G > I
II. X ≥ L
III. L < L
Statements: 1 > 2 ≥ 3 = 4 < 5 ≤ 6; 7 ≥ 8 = 9 < 4 = 10 ≥ 11
Conclusions:
I. 2 ≥ 10
II. 3 < 7
III. 6 > 11
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ K ≤ B
Conclusions:I. U ≥ E II. S > T