Question
Which of the following methods is most appropriate for
forecasting future values in time series data with a consistent trend and seasonality?Solution
Exponential smoothing is one of the most effective forecasting methods when dealing with time series data that exhibits both trend and seasonality. It assigns exponentially decreasing weights to past observations, which means that more recent data points have a greater influence on the forecast. The method adapts well to data with trends and seasonal variations because it accounts for these patterns in its calculation. Variants such as Holt-Winters exponential smoothing are used specifically when the data shows seasonality and trend components, making it suitable for time series forecasting where such features are evident. Why Other Options Are Incorrect: • A: Moving averages are useful for smoothing time series data but do not explicitly handle trends and seasonality as well as exponential smoothing. • B: ARIMA (AutoRegressive Integrated Moving Average) is a powerful method but is more complex and suitable for non-seasonal data or when seasonality is handled separately through seasonal ARIMA (SARIMA). • D: Random Forest is a machine learning model and is not typically used for forecasting time series data that shows clear seasonality and trend. • E: Linear regression is more suitable for predicting values based on independent variables, not for time series forecasting where autocorrelation and seasonality are crucial.
[192 ÷ 6 × 5] ÷ (? + 3) = 20Â
What will come in the place of question mark (?) in the given expression?
(125 × 64) ÷ (8 × 5) + (12.5)² – (144 ÷ 3) = ?
...What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751Â
The income of a person is Rs.15000 and his expenditure is Rs.12000. In the next year his income and expenditure is increased by 8% and 13% respectively....
15% of 695 – 12.5% of 250 =? – 1200
Simplify the following expressions and choose the correct option.
{[(96 ÷ 3) × (5/8)] + 7²} ÷ 9 = ?
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2Â
Evaluate: 84 ÷ 7 × (3 + 5) − 2³
31% of 1900 - ? = 73
535 + ? × 27 - 22 × 20 = 230Â