Question
In a relational database, which key uniquely identifies
tuples within a table and can never contain NULL values?Solution
A Primary Key uniquely identifies each record (or tuple) in a table and cannot contain NULL values. It enforces entity integrity, ensuring that every row in a table has a unique identifier. For example, in a table of employees, an employee ID serves as a primary key, ensuring no duplicate or NULL entries exist. Why Other Options Are Incorrect:
- Foreign Key: Links one table to another and can contain NULL values in some cases; its purpose is to enforce referential integrity, not uniqueness within its table.
- Candidate Key: A potential key that can uniquely identify tuples but is not chosen as the primary key.
- Alternate Key: A candidate key not selected as the primary key but still capable of uniquely identifying records.
- Composite Key: A primary key consisting of multiple columns but is a type of primary key, not a separate concept.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 97x² - 436x + 339 = 0
Equation 2: 103y² - 460y + 357 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 2x² + 11 x + 15 = 0  Â
II. 2y² - 19 y + 44 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I. 3y2 + 16y + 16 = 0
II. 2x2 + 19x + 45 = 0
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)