Question
A person throws a ball from ground level at speed u and
angle θ. The ball reaches maximum height H and range R. What is the ratio H/R?Solution
Given:
- Maximum height: H = (u²·sin²θ) / (2g)
- Range: R = (u²·sin2θ) / g
= sin²θ / (2·sin2θ) Now use the identity: sin2θ = 2·sinθ·cosθ So, H/R = sin²θ / [2·(2·sinθ·cosθ)] = sinθ / (4·cosθ) = (1/4)·tanθ
More Physics GS Questions
What will come in place of the question mark (?) in the following series?
50, 70, 110, 190, 310, ?
58, 67, ?, 76, 40, 85
415 246 367 ? 335 310
...97, 106, ?, 195, 411, 460
Find the missing character.
What will come in place of the question mark (?) in the following series?
100, 81, 64, 51, 40, ?
110, 112, 116, 122, 130, ?
18, 37, 60, ?, 120, 157
64, 80, 120, 210, ?, 945
86, 127, ?, 209, 250, 291
Relevant for Exams:
