New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Two capacitors, 2 µF and 3 µF, are charged separately

    to 100 V and 50 V respectively, and then connected positive to positive, negative to negative. Find the loss in energy due to redistribution.
    A 2.5 mJ Correct Answer Incorrect Answer
    B 4.0 mJ Correct Answer Incorrect Answer
    C 1.5 mJ Correct Answer Incorrect Answer
    D 3.0 mJ Correct Answer Incorrect Answer

    Solution

    We are given:

    • Capacitor 1: C₁ = 2 µF, charged to V₁ = 100 V
    • Capacitor 2: C₂ = 3 µF, charged to V₂ = 50 V
    • They are connected positive to positive, negative to negative ⇒ charges redistribute, no reversal of polarity
    • We are to find the loss in energy after redistribution
    The initial energy stored in the first capacitor (C1 = 2μF, V1 = 100V) is:

    Practice Next

    Relevant for Exams: