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    • Question

      Two capacitors, 2 µF and 3 µF, are charged separately

      to 100 V and 50 V respectively, and then connected positive to positive, negative to negative. Find the loss in energy due to redistribution.
      A 2.5 mJ Correct Answer Incorrect Answer
      B 4.0 mJ Correct Answer Incorrect Answer
      C 1.5 mJ Correct Answer Incorrect Answer
      D 3.0 mJ Correct Answer Incorrect Answer

      Solution

      We are given:

      • Capacitor 1: C₁ = 2 µF, charged to V₁ = 100 V
      • Capacitor 2: C₂ = 3 µF, charged to V₂ = 50 V
      • They are connected positive to positive, negative to negative ⇒ charges redistribute, no reversal of polarity
      • We are to find the loss in energy after redistribution
      The initial energy stored in the first capacitor (C1 = 2μF, V1 = 100V) is:

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