Question
A 5 kg block at rest is hit by a 0.1 kg bullet moving at
500 m/s. The bullet gets embedded into the block. What is their final velocity?Solution
We are given:
- Bullet mass = 0.1 kg, initial speed = 500 m/s
- Block mass = 5 kg, initially at rest
- The bullet gets embedded into the block (i.e., perfectly inelastic collision)
- We are to find the final velocity (Vf) of the bullet-block system after collision
- Bullet: pā Ā = 0.1 Ć 500 = 50 kgĀ·m/s
- Block: pā Ā = 5 Ć 0 = 0
- Total initial momentum = 50 kgĀ·m/s
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