Question
The energy stored in a stretched spring
is:Solution
The potential energy stored in a stretched or compressed spring follows Hooke’s Law: U = 1/2 kx² Here, k is the spring constant and x is the displacement from the natural length. This energy is due to the work done in stretching or compressing the spring. So, correct expression is 1/2 kx².
1001, 728, 513, 342, 217, ?
13 22 40 67 103 ?
...3  16  22  ?   98   206
25Â Â Â Â Â Â Â Â Â Â 34Â Â Â Â Â Â Â Â Â Â 61Â Â Â Â Â Â Â Â Â Â 106Â Â Â Â Â Â Â Â 169Â Â Â Â Â Â Â Â ?
...3 2 10 ? 17 16
...18 113 559 2247 6721 13451
...If 2.5 3.5 x 30 124 625
Then, x ² - 1 - 2x = ?
...64Â Â Â Â Â Â 66Â Â Â Â Â Â Â 76Â Â Â Â Â Â 126Â Â Â Â Â Â 376Â Â Â Â Â Â Â ?
...To find the Next number in the given series.
342 510 726 996 1326 ?
...8, 9, 15, ?,82.5, 250.50
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