Question
Two capacitors of 4 μF and 6 μF are connected in
series. The equivalent capacitance is:Solution
For capacitors in series: 1/Ceq = 1/C₁ + 1/C₂ = 1/4 + 1/6 = 5/12 So, Ceq = 12/5 = 2.4 μF Hence, the correct equivalent capacitance is 2.4 μF.
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