Question
The stopping potential for photoelectrons emitted from
a metal surface when light of frequency 8×1014 Hz is incident is 3 V. What is the work function of the metal?Solution
Given:
- Frequency of incident light: f = 8 × 10¹⁴ Hz
- Stopping potential: V₀ = 3 V
- h is Planck's constant (6.626 × 10⁻³⁴ J·s)
- f is the frequency of incident light
- Φ is the work function we need to find
- KEmax is the maximum kinetic energy of ejected electrons
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