Question
A parallel plate capacitor is half-filled with a
dielectric slab (K = 4). What is its effective capacitance, assuming plate separation d?Solution
Let the parallel plate capacitor have plates of area A and separation d. The original capacitance without the dielectric is When a dielectric slab of thickness d/2 and dielectric constant K=4 is inserted, the capacitor can be considered as two capacitors connected in series: 1. A capacitor with air (or vacuum, K=1) and plate separation d/2. Its capacitance
2. A capacitor with the dielectric (K=4) and plate separation d/2. Its capacitance
The effective capacitance Ceff of two capacitors in series is given by:
Therefore the correct answer is option (A).
?% of (168 ÷ 8 × 20) = 126
25% of 140 + 2 × 8 = ? + 9 × 5
- What will come in place of (?), in the given expression.
(56 × 3) + (480 ÷ 6) = ? 641.5 + 72 × 8 = ? × 4
Simplify-
x + 3(y + x – 2) – (x + y).
What will come in the place of question mark (?) in the given expression?
412 + 25% of 2400 = ? + 1131
[∛(3375/19683 )- ∛(125/1728 ) ] ÷ ∛(64/729) = ? - 3/8
8 × 12 + 110 ÷ 5 = 72 + ?
28 × 3.5 +25 × 3.2 = ? - 62
[∛(91125/19683 )- ∛(3375/5832 ) ] × ∛(512/9261) = ? - √(484/3969)