A body starts from rest and accelerates uniformly. After t seconds, it covers a distance S. What is the ratio of the distance covered in the first half to the second half of time?

Given:

• A body starts from rest , so initial velocity u = 0
• It moves with uniform acceleration a
• Total time of motion = t seconds
• Total distance covered in time t = S

We are asked to find the ratio of distance covered in the first half of time (i.e., from 0 to t/2​) to the second half (i.e., from t/2 to t). Total Distance Covered in Time t Using the formula for distance under uniform acceleration: Since u = 0, this becomes: Distance Covered in First Half of Time (0 to t/2​) Again, using the same formula: Distance Covered in Second Half (t/2 to t) The total distance in time t is S = (1/2)at², and we've already found distance in first half is S1 = at²/8 So the distance covered in second half: Ratio of First Half to Second Half