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      Question

      A body starts from rest and accelerates uniformly. After

      t seconds, it covers a distance S. What is the ratio of the distance covered in the first half to the second half of time?
      A 1:1 Correct Answer Incorrect Answer
      B 1:2 Correct Answer Incorrect Answer
      C 1:3 Correct Answer Incorrect Answer
      D 3:1 Correct Answer Incorrect Answer

      Solution

      Given:

      • A body starts from rest , so initial velocity u = 0
      • It moves with uniform acceleration a
      • Total time of motion = t seconds
      • Total distance covered in time t = S
      We are asked to find the ratio of distance covered in the first half of time (i.e., from 0 to t/2​) to the second half (i.e., from t/2 to t). Total Distance Covered in Time t Using the formula for distance under uniform acceleration: Since u = 0, this becomes: Distance Covered in First Half of Time (0 to t/2​) Again, using the same formula: Distance Covered in Second Half (t/2 to t) The total distance in time t is S = (1/2)at2, and we've already found distance in first half is S1 = at2/8 So the distance covered in second half: Ratio of First Half to Second Half

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