New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    A body starts from rest and accelerates uniformly. After

    t seconds, it covers a distance S. What is the ratio of the distance covered in the first half to the second half of time?
    A 1:1 Correct Answer Incorrect Answer
    B 1:2 Correct Answer Incorrect Answer
    C 1:3 Correct Answer Incorrect Answer
    D 3:1 Correct Answer Incorrect Answer

    Solution

    Given:

    • A body starts from rest , so initial velocity u = 0
    • It moves with uniform acceleration a
    • Total time of motion = t seconds
    • Total distance covered in time t = S
    We are asked to find the ratio of distance covered in the first half of time (i.e., from 0 to t/2​) to the second half (i.e., from t/2 to t). Total Distance Covered in Time t Using the formula for distance under uniform acceleration: Since u = 0, this becomes: Distance Covered in First Half of Time (0 to t/2​) Again, using the same formula: Distance Covered in Second Half (t/2 to t) The total distance in time t is S = (1/2)at2, and we've already found distance in first half is S1 = at2/8 So the distance covered in second half: Ratio of First Half to Second Half

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