Question
A body starts from rest and accelerates uniformly. After
t seconds, it covers a distance S. What is the ratio of the distance covered in the first half to the second half of time?Solution
Given:
- A body starts from rest , so initial velocity u = 0
- It moves with uniform acceleration a
- Total time of motion = t seconds
- Total distance covered in time t = S
Since u = 0, this becomes: 
Distance Covered in First Half of Time (0 to t/2​) Again, using the same formula: 
Distance Covered in Second Half (t/2 to t) The total distance in time t is S = (1/2)at2, and we've already found distance in first half is S1 = at2/8 So the distance covered in second half: 
Ratio of First Half to Second Half 
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